4(x^2-2)=4x^2+2x+6

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Solution for 4(x^2-2)=4x^2+2x+6 equation: 



4(x^2-2)=4x^2+2x+6

We move all terms to the left:

4(x^2-2)-(4x^2+2x+6)=0

We multiply parentheses

4x^2-(4x^2+2x+6)-8=0

We get rid of parentheses

4x^2-4x^2-2x-6-8=0

We add all the numbers together, and all the variables

-2x-14=0

We move all terms containing x to the left, all other terms to the right

-2x=14

x=14/-2

x=-7

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